This article was posted to the Usenet group alt.hackers in
1995; any technical information is probably outdated.
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Re: A challenge for UNIX wizards
Article: 7883 of alt.hackers Newsgroups: alt.hackers From: cmcurtin@clipper.cb.att.com (C Matthew Curtin) Subject: Re: A challenge for UNIX wizards Message-ID: D95J9o.HCI@nntpa.cb.att.com Sender: news@nntpa.cb.att.com (Netnews Administration) Nntp-Posting-Host: clipper.cb.att.com Organization: AT&T Bell Labs Date: Thu, 25 May 1995 20:51:24 GMT Approved: By 90% of all the world's UNIX wizards. Lines: 27 Status: RO
In article <3q185g$3je@lll-winken.llnl.gov>,
Sam Trenholme <set@oryx.llnl.gov> wrote:
>Ok guys, is there a way of doing this without using a temporary file:
>
>ls | awk 'BEGIN{FS="."}{print "mv "$0"
"$1".1"}' > l;chmod 700 l;l;rm l
>
>(The above made a list of files, foo.man, bar.man, etc. have the names
>foo.1, bar.1, etc)
Just to make sure I understand: You want to take a directory full of
files names something.man and turn them all into something.1, without
using any temp files? That's easy :-)
ObMiniHack:
We're assuming ksh (or at least sh) here... Just type this off of the
command line:
for x in `ls *.man`
do
mv $x `ls $x | sed s/\.man/\.1/g`
done
Aren't regular expressions great?
--
C Matthew Curtin
AT&T Bell Labs - Internet Gateway Group
cmcurtin@clipper.cb.att.com
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